Question

$sin(2x-n/6)=0$ (c ходом решения)

Answer 1

$\displaystyle\bf\\Sin\Big(2x-\frac{\pi }{6} \Big)=0\\\\\\2x-\frac{\pi }{6} =\pi n \ , \ n\in Z\\\\\\2x=\frac{\pi }{6} +\pi n \ , \ n\in Z\\\\\\\boxed{x=\frac{\pi }{12} +\frac{\pi n}{2} \ , \ n\in Z}$