Question

Для функції f(x)=x²+2x знайдіть : f(0) , f(-1) , f(2) , f(-3)​

Answer 1

Ответ:

$f(x) = {x}^{2} + 2x \\ f(0) = {0}^{2} + 2 \times 0 = 0 \\ f( - 1) = {( - 1)}^{2} + 2 \times ( - 1) = 1 - 2 = - 1 \\ f(2) = {2}^{2} + 2 \times 2 = 4 + 4 = 8 \\ f( - 3) = {( - 3)}^{2} + 2 \times ( - 3) = 9 - 6 = 3$