Question

срочно пожалуйста...!!​

Answer 1

$\displaystyle 1)(-\frac{2a}{3b})^3*(\frac{1}{a})^2=-(\frac{2a}{3b})^3*\frac{1}{a^2}=-\frac{8a^3}{27b^3}*\frac{1}{a^2}=-\frac{8a}{27b^3}\\\\ 2)(\frac{6}{7x})^2:(-\frac{2}{x})^3=(\frac{6}{7x})^2:(-(\frac{2}{x})^3)=-\frac{36}{49x^2}:\frac{8}{x^3}=-\frac{36}{49x^2}*\frac{x^3}{8}=-\frac{9}{49}*\frac{x}{2}=\\ \\ -\frac{9x}{98}$