Question

Срочно!!!!
Алгебра 8 класс, помогите.
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Answer 1

$\displaystyle 1)(x-7)^3(x+4)=0\\(x-7)^3=0,x+4=0\\x_{1}=-4,x_{2}=7\\\\ 2)x^3-3x^2-4x=0\\x(x^2-3x-4)=0\\x(x^2+x-4x-4)=0\\x(x(x+1)-4(x+1))=0\\x(x+1)(x-4)=0\\x=0,x+1=0,x-4=0\\x_{1}=-1,x_{2}=0,x_{3}=4\\\\ 3)\frac{x^2-36}{x^2-7x+6}=0,x\neq 1;x\neq 6\\\\ \frac{(x-6)(x+6)}{x^2-x-6x+6}=0\\\\ \frac{(x-6)(x+6)}{x(x-1)-6(x-1)}=0\\\\ \frac{(x-6)(x+6)}{(x-1)(x-6)}=0\\\\ \frac{x+6}{x-1}=0\\\\ x+6=0\\x=-6$