Question

помогите с алгеброй ​

Answer 1

(а+5)(3а+1) = 3а²+а+15а+5 = 3а²+16а+5

(х-5)(2х-3) = 2х²-3х-10х+15 = 2х²-13х+15

(2-х)(х-1)-(х+1)(х+2) = (2х-2-х²+х)-(х²+2х+х+2) = -х²+3х-2-х²-3х-2 = -2х²-4

(3х+3)(5-х)-(5х-5)(3х-2) = (15х-3х²+15-3х)-(15х²-10х-15х+10) = -3х²+12х+15-15х²+25х-10 = -18х²+37х+5

Answer 2

Ответ:

1.(a+5)(3a+1)=3a ²+a+15a+5=3a ²+16а+5

2.(x−5)(2x−3)=2x²−3x−10x+15=2x²−13x+15

3.(2−x)(x−1)+(x+1)(x+2)=

2x−2−x²+x+(x+1)(x+2)=3x−2−x²+x²+2x+x+2=3x−2+3x+2=

6x−2+2=6x

4.(3x+3)(5−x)−(5x−5)(3x−2)=

15x−3x  ²+15−3x−(5x−5)(3x−2)

=12x−3x²+15−(15x²   −10x−15x+10)

=12x−3x²  +15−15x² −(−25x)−10

=37x−18x²  +15−10

=37x−18x²  +5

Объяснение: