Question

найти производную. срочно!!​

Answer 1

Ответ:

$y=\dfrac{arcsin(4x+5)}{\sqrt[5]{ln^4(\frac{1}{x})}}\\\\\\y'=\dfrac{\dfrac{1}{\sqrt{1-(4x+5)^2}}\cdot 4\cdot \sqrt[5]{ln^4(\frac{1}{x})}-arcsin(4x+5)\cdot \dfrac{4}{5}\cdot \Big(ln\frac{1}{x}\Big)^{-\frac{1}{5}}\cdot x\cdot \dfrac{-1}{x^2}}{\sqrt[5]{ln^8(\frac{1}{x})}}=\\\\\\=\dfrac{\dfrac{1}{\sqrt{1-(4x+5)^2}}\cdot 4\cdot \sqrt[5]{ln^4(\frac{1}{x})}+arcsin(4x+5)\cdot \dfrac{4}{5x\, \sqrt[5]{ln\frac{1}{x}}}}{\sqrt[5]{ln^8(\frac{1}{x})}}$