Question

решите систему уравнений​

Answer 1

Ответ:

Объяснение:

$\displaystyle\\x\neq y;x\neq -y\\\\\left \{ {{\dfrac{2}{x-y}+\dfrac{12}{x+y} =1~~~~~~~~~~|\cdot5 } \atop {\dfrac{6}{x-y}-\dfrac{20}{x+y} =-11~~~~~~~|\cdot3}} \right. \\\\\\\left \{ {{{\dfrac{10}{x-y}+\dfrac{60}{x+y} =5} \atop {{\dfrac{18}{x-y}-\dfrac{60}{x+y} =-33}} \right. \\+\\------------\\\\\frac{28}{x-y} =-28;~\frac{1}{x-y} =-1;~x-y=-1;~x=y-1\\\\\dfrac{2}{x-y}+\dfrac{12}{x+y} =1\\\\\dfrac{2}{y-1-y}+\dfrac{12}{y-1+y} =1\\\\-2+\frac{12}{2y-1} =1\\\\\frac{12}{2y-1}=3;~\frac{4}{2y-1} =1;2y-1=4;2y=5;y=2,5$

$x=y-1=2,5-1=1,5\\\\Otvet(1,5;2,5)$