Question

Довести тотожність
(4х2-3х-4у)+(2х2-3х)-(-у2+6х2-6х)=у2-4у

Answer 1

$(4 {x}^{2} - 3x - 4y) + (2{x}^{2} - 3x) - ( - {y}^{2} + 6 {x}^{2} - 6x) = 4 {x}^{2} - 3x - 4y + 2 {x}^{2} - 3x + {y}^{2} - 6 {x}^{2} + 6x \bf\equiv {y}^{2} - 4y. \\ \bf \huge \: tozhdestvo \: \: \: \: dokazano.$