Question

помогите пж геометрия 7клас​

Answer 1

Ответ:

1) 27 - 32 = -5

2) 0.4 × 25 + 0.3 × (-216) = 10 - 64.8 = -54.8

1) y^6×y^9= y^15

2)(y^6)^9= y^54

3)a^19 ÷ a^3 = a^16

4) (-2c)^4= 16c^4

Answer 2

Номер 1

$1) \: 3 {}^{3} - {2}^{5} = - 5$

$2)0.4 \times ( - 5) {}^{2} + 0.3 \times ( - 6) {}^{3} = - 54.8$

Номер 2

$1) \: y {}^{6} \times y {}^{9} = y {}^{15}$

$2) \: (y {}^{6} ) {}^{9} = y {}^{54}$

$3) \: a {}^{19} \div a {}^{3} = a {}^{16}$

$4) \: ( - 2c) {}^{4} = 16c {}^{4}$