Question

помогите пожалуйста решать эту задачу ​

Answer 1

Ответ:

$25 {a}^{4} \times {(3 {a}^{3}) }^{2} = 25 {a}^{4} \times {3}^{2} {a}^{3 \times 2} = 25 {a}^{4} \times 9 {a}^{6} = (25 \times 9) {a}^{4 + 6} = 225 {a}^{10}$

${( - 3 {b}^{6}) }^{4} \times b = {( - 3)}^{4} {b}^{6 \times 4} = 81 {b}^{24} \times b = 81 {b}^{24 + 1} = 81 {b}^{25}$

$8 {p}^{15} \times {( - p)}^{4} = 8 {p}^{15} \times - {p}^{4} =- 8 {p}^{15 + 4} = - 8 {p}^{19}$

${( { - c}^{2}) }^{3} \times 0.15 {c}^{4} = - {c}^{2 \times 3} \times 0.15 {c}^{4} = - {c}^{6} \times 0.15 {c}^{4} = - 0.15 {c}^{6 + 4} = - 0.15 {c}^{10}$

${( { - 10c }^{2} )}^{4} \times 0.0001 {c}^{11} = {( - 10)}^{4} {c}^{2 \times 4} \times 0.0001 {c}^{11} = 10000 {c}^{8} \times 0.0001 {c}^{11} =(10000 \times 0.0001) {c}^{8 + 11} = {c}^{19}$