Question

k+4/k-4:k²-8k+16/k2-16​

Answer 1

   $\frac{k+4}{k-4} :\frac{k^2-8k+16}{k^2-16} =$

$=\frac{k+4}{k-4} :\frac{(k-4)^2}{k^2-4^2} =$

$=\frac{k+4}{k-4} :\frac{(k-4)(k-4)}{(k-4)(k+4)} =$

$=\frac{k+4}{k-4} :\frac{k-4}{k+4} =$

$=\frac{k+4}{k-4}*\frac{k+4}{k-4} =$

$=\frac{(k+4)^2}{(k-4)^2}$