Question

(3х-1)*(3х-1)-(3х-2)(3х-2)=0
(3х+2)(3х-2)-(3х-4)(3х-4)=28
(3х+4)(3х+4)-(3х-1)(1+3х)=89
(7-2х)-(2х+3)(2х-3)=100

Answer 1

Ответ:

(3х-1)(3х-1)-(3х-2)(3х-2)=0

9x^2-6x+1-9x^2+6x+6x-4=0

6x-3=0

(3х+2)(3х-2)-(3х-4)(3х-4)=28

9x^2-6x-6x+4-9x^2+24x-16=28

12x-12-28=0

12x-16=0 /:4

3x-4=0

3x=4

x=1.3

(3х+4)(3х+4)-(3х-1)(1+3х)=89

9x^2-24x+16-9x^2+1=89

-24x+17+89

-24x=72

x=-3

(7-2х)-(2x+3)(2х-3)=100

7-2x-4x^2+9=100

-4x^2-2x+16-100=0

-4x^2-2x-84=0 /*(-1

Natalia1515151 avatar

-4x^2-2x-84=0 /*(-1)

4x^2+2x+84=0 /:2

2x^2+x+42=0

D=1-4*42*2=1-336=335=18.3^2

x1=(-1-18.3)/4=4.8;x2=(-1+18.3)/4=4.3

Объяснение: