Question

(6-2a) (a^2+5a) +2a(a+5) (a-3) при a=0, 1

Срочно надо

Answer 1

$\bf (6 - 2a)( {a}^{2} + 5a) + 2a(a+5)(a - 3) = 6 {a}^{2} + 30a - 2 {a}^{3} - 10 {a}^{2} + 2 {a}^{3} - 6 {a}^{2} + 10 {a}^{2} - 30a = \huge0$