Question

x^3-(4x+x^2) (x-4) при x=1/16

Answer 1

$\bf \: {x}^{3} - (4x + {x}^{2} )(x - 4) = {x}^{3} - (4 {x}^{2} - 16x + {x}^{3} - 4 {x}^{2} ) = 16x = 16 \times \frac{1}{16} = \huge1$