Question

б) (b³- b²)(b³+b²) - (1 + b²)(1 - b² + b⁴) при b = 0.1 6) ​

Answer 1

$(b^3-b^2)(b^3+b^2)-(1+b^2)(1-b^2+b^4)=(b^3)^2-(b^2)^2-(1^3+(b^2)^3)=\\\\=b^6-b^4-1-b^6=-1-b^4=-(1+b^4)\\\\b=0.1\\\\-(1+(0.1)^4)=-(1+0.0001)=-1.0001$