Question

(2x2+7x-8)(2x2+7x-3)=6​

Answer 1

Ответ:

2x^2+7x=t

(t-8)(t-3)-6=0

t²-11t+24-6=0

t²-11t+18=0

D=121-4×18=121-72=49 √D=7

t1=(11-7)/2=2

2x²+7x-2=0

D=49+16=65 √D=√65

x1=(-7+√65)/4

x2=(-7-√65)/4

t2=18/2=9

2x²+7x-9=0

D=49+18×4=121 √D=11

x1=(-7+11)/4=1

x2=(-18)/4