Question

6x^2-(2-3x)(3-2x)=7 будласка треба развязаты

Answer 1

$6x {}^{2} - (2 - 3x)(3 - 2x) = 7 \\ 6x {}^{2} - (6 - 4x - 9x + 6x {}^{2} ) = 7 \\ 6x {}^{2} - (6 - 13x + 6x {}^{2} ) = 7 \\ 6x {}^{2} - 6 + 13x - 6x {}^{2} = 7 \\ - 6 + 13x = 7 \\ 13x = 7 + 6 \\ 13x = 13 \\ x = 1$

Answer 2

Объяснение:

$6x {}^{2} - (2 - 3x)(3 - 2x) = 7 \\ 6x {}^{2} - (6 -1 3x + 6x {}^{2} ) = 7 \\ 6x {}^{2} - 6 + 13x - 6x {}^{2} = 7 \\ - 6 + 13x = 7 \\ 13x = 7 + 6 \\ 13x = 13 \\ x = 13 \div 13 \\ x = 1$