Question

2sin(x-pi)=корень из 2
ПОМОГИТЕ УМОЛЯЮ​

Answer 1

$2sin(x-\pi)=\sqrt{2}\\\\sin(x-\pi)=\frac{\sqrt{2}}{2}\\\\-sin(\pi -x)=\frac{\sqrt{2}}{2}\\\\-sinx= \frac{\sqrt{2}}{2}\\\\sinx=-\frac{\sqrt{2}}{2}\\\\x=(-1)^{n+1}*arcsin\frac{\sqrt{2}}{2} +\pi n, n\in Z\\\\x=(-1)^{n+1}*\frac{\pi}{4}+\pi n, n\in Z$