Question

 (x+1)^2-(x-2)(x+2)=7 решите срочно

Answer 1

$x^{2}+2x+1-x^{2}+4=7 \ 2x=2 \ x=1$

Answer 2

 (x+1)²-(x-2)(x+2)=7
x²+2x+1-(x²-4)=7
x²+2x+1-x²+4=7
2x=7-5
2x=2
x=1