Question

СРОЧНО ПОМОГИТЕ СРОЧНО

Answer 1

Ответ:

Объяснение:

$\frac{a+6a^{\frac{1}{4}}}{a^{\frac{3}{4}}+6}=\frac{a^{\frac{1}{4}}(a^{\frac{3}{4}}+6)}{a^{\frac{3}{4}}+6}=a^{\frac{1}{4}}$

$\frac{a-b}{a^{0,5}+b^{0,5}}=\frac{a-b}{a^{\frac{1}{2}}+b^{\frac{1}{2}}}=\\=\frac{(a^{\frac{1}{2}})^2-(b^{\frac{1}{2}})^2}{a^{\frac{1}{2}}+b^{\frac{1}{2}}}=\\=\frac{(a^{\frac{1}{2}}+b^{\frac{1}{2}})(a^{\frac{1}{2}}-b^{\frac{1}{2}})}{a^{\frac{1}{2}}+b^{\frac{1}{2}}}=a^{\frac{1}{2}}-b^{\frac{1}{2}}=a^{0,5}-b^{0,5}$

$\frac{x-5x^{\frac{1}{5}}}{x^{\frac{6}{5}}-5x^{\frac{2}{5}}}=\frac{x^{\frac{1}{5}}(x^{\frac{4}{5}}-5)}{x^{\frac{2}{5}}(x^{\frac{4}{5}}-5)}=$

$=\frac{x^{\frac{1}{5}}}{x^{\frac{2}{5}}} =x^{\frac{1}{5}-\frac{2}{5}}=x^{-\frac{1}{5} }=\frac{1}{x^{\frac{1}{5}}}$