Question

корень(2x-3)^2 при x=0 x=1 x=-2 x=-3
ПОМОГИТЕ ​

Answer 1

Ответ:

$\sqrt{(2 \times 0 - 3) {}^{2} } = \sqrt{( - 3) {}^{2} } = \\ \sqrt{9} = 3$

$\sqrt{(2 \times 1 - 3) {}^{2} } = \sqrt{( - 1) {}^{2} } = \\ \sqrt{1} = 1$

$\sqrt{ {(2 \times ( - 2) - 3)}^{2} } = \sqrt{( - 7) {}^{2} } \\ = \sqrt{49} = 7$

$\sqrt{(2 \times ( - 3) - 3) {}^{2} } = \sqrt{( - 9) {}^{2} } \\ = \sqrt{81} = 9$