Question

х²+7х+2=0 через дискриминат​

Answer 1

Ответ:

${x}^{2} + 7x + 2 = 0 \\ d = ( {7)}^{2} - 4 \times 2 \times 1 = 49 - 8 = 41 \\ = \sqrt{41} \\ x1 = \frac{ - 7 + \sqrt{41} }{2}$

$x2 = \frac{ - 7 - \sqrt{41} }{2}$

Answer 2

$\displaystyle x^2+7x+2=0\\D = b^2-4ac=7^2-4*1*2=49-8=41\\\\ x_{1}=\frac{-7-\sqrt{41} }{2},x_{2}=\frac{-7+\sqrt{41} }{2}$