Question

3х²+2х-1=0 дискриминат арқылы шешу ​

Answer 1

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Answer 2

$\displaystyle3x^2+2x-1=0\\D = b^2-4ac=2^2-4*3*(-1)=4+12=16\\\\ x_{1}=\frac{-2-\sqrt{16} }{2*3}=\frac{-2-4}{6}=\frac{-6}{6}=-1\\\\ x_{2}=\frac{-2+\sqrt{16} }{2*3}=\frac{-2+4}{6}=\frac{2}{6}=\frac{1}{3}$