Предмет: Геометрия, автор: lizag0572

помогите пожалуйста

Приложения:

Ответы

Автор ответа: maksimstrutinskij

Ответ:

BD бісиктриса

тому трикутники ABD = DBC

тому AB = BC

Автор ответа: braduk07

Ответ:

Объяснение:

АD=CD поэтому треугольник ACD равнобедренный.

BDбиссектриса т к угол CDB=ADB, поэтому в равнобедренном треугольнике биссектриса проведенная к основанию равна медиане и высоте. Медиана делит AC на две равные части

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