Question

X - - 2 X Вариант 3 1. 4y - y2 = 0 - 2. 0,2y? - y = 0 3. (x + 2)(x - 1) = 0) 4. (x - 0,3)x = 0 5. x2 + 4x = 0 6. x2 – 36 = 0 0 7. 16x² – 1 = 0 8. 4x - 5x2 = 0 9. x² = 7x 10. x² – 3x – 5 = 11 – 3x 11. 5x2 - 6= 15x - 6 12. X2 – 2x = 0 13. x? - 16 = 0 14. 15. 16. 17. 2 - - 2 (x + 1)(x-2) = 0 x(x + 0,5) = 0 (x + 1)2 – 4= 0 3x2 + 7 = 12x+ 7 2 пожалуйста решение и ответ ​

Answer 1

Ответ:

$4y - {y}^{2} = 0 \\ y(4 - y) = 0 \\ 1)y = 0 \\ 2)4 - y = 0 \\ - y = - 4 \\ y = 4$

$0.2 {y}^{2} - y = 0 \\ y(0.2y - 1) = 0 \\ 1)y = 0 \\ 2)0.2y - 1 = 0 \\ 0.2y = 1 \\ \frac{2}{10} y = 1 \\ y = 1 \times \frac{10}{2} \\ y = 5$

$(x + 2)(x - 1) = 0 \\ 1)x + 2 = 0 \\ x = - 2 \\ 2)x - 1 = 0 \\ x = 1$

$(x - 0.3)x = 0 \\ 1)x - 0.3 = 0 \\ x = 0.3 \\ 2)x = 0$

${x}^{2} + 4x = 0 \\ x(x + 4) = 0 \\ 1)x = 0 \\ 2)x + 4 = 0 \\ x = - 4$

${x}^{2} - 36 = 0 \\ (x - 6)(x + 6) = 0 \\ 1)x - 6 = 0 \\ x = 6 \\ 2)x + 6 = 0 \\ x = - 6$

$16 {x}^{2} - 1 = 0 \\ (4x - 1)(4x + 1) = 0 \\ 1)4x - 1 = 0 \\ 4x = 1 \\ x = \frac{1}{4} \\ 2)4x + 1 = 0 \\ 4x = - 1 \\ x = - \frac{1}{4}$

$4x - 5 {x}^{2} = 0 \\ x(4 - 5x) = 0 \\ 1)x = 0 \\ 2)4 - 5x = 0 \\ - 5x = 0 - 4 \\ - 5x = - 4 \\ x = \frac{4}{5}$

${x}^{2} = 7x \\ {x}^{2} - 7x = 0 \\ x(x - 7) = 0 \\ 1)x = 0 \\ 2)x - 7 = 0 \\ x = 7$