Question

Срочно с алгеброй помогите 15 баллов

Answer 1

Ответ:

9 27

Объяснение:

$log_{a}b = \frac{1}{log_{b}a }$ - свойство логарифма

1/logx(3) + 6logx(3) = 5  | x>0; x$\neq 1$

(1+6logx(3) * logx(3))/logx(3) = 5 | * logx(3)

1 + 6logx(3)^2 = 5logx(3)  | t=logx(3)

6t^2 - 5t +1=0

D=1

t1 = 5+1/12 = 1/2

t2 = 5-1/12 = 1/3

logx(3) = 1/2 --> x^1/2 = 3   x = 9

logx(3) = 1/3 --> x^1/3 = 3    x = 27