Question

Помогите пожалуйста ​

Answer 1

Ответ:

${x}^{2} + 3x + 5 = 9 \\ \\ {x}^{2} + 3x + 5 - 9 = 0 \\ \\ {x}^{2} + 3x - 4 = 0 \\ (x + 4)(x - 1) = 0 \\ \\ x_{1} = - 4 \\ x_{2} = 1$

$\sqrt{( - 4) ^{2} + 3 \times ( - 4) + 5} = 3 \\ \sqrt{16 - 12 + 5} = 3 \\ \sqrt{9} = 3 \\ 3 = 3$

$\sqrt{1^{2} + 3 \times 1 + 5 } = 3 \\ \sqrt{1 + 3 + 5} = 3 \\ \sqrt{9} = 3 \\ 3 = 3$

Ответ:

$x_{1} = - 4 \\ x_{2} = 1$