Question

пжпжп я отдам 50б мне ето нужно
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Answer 1

Ответ:

$(2 \frac{2}{9} + \frac{5}{6} ) \div \frac{5}{9} = (2 \frac{3}{5} \times 1 \frac{2}{13} + x) \div 6.2 \\ a \div \frac{5}{9} = (b + x) \div \frac{62}{10} \\ \frac{9a}{5} = \frac{10(b + x)}{62} \\ 9a \times 62 = 5 \times 10(b + x) \\ 558a = 5 \times (10b + 10x) \\ 558a = 50b + 50x \\ 50x = 558a - 50b \\ x = \frac{558a - 50b}{50} \\ \\ x = \frac{558 \times (2 \frac{2}{9} + \frac{5}{6} ) - 50 \times (2 \frac{3}{5} \times 1 \frac{2}{13}) }{50} \\ x = \frac{558 \times ( \frac{20}{9} + \frac{5}{6}) - 50 \times ( \frac{13}{5} \times \frac{15}{13} ) }{50} \\ x = \frac{558 \times \frac{20}{9} + 558 \times \frac{5}{6} - 50 \times 3}{50} \\ x = \frac{62 \times 20 + 93 \times 5 - 150}{50} \\ x = \frac{1240 + 465 - 150}{50} \\ x = \frac{1555}{50} \\ x = 31.1$