Предмет: Биология, автор: vladislglagolev

В процессе гликолиза образовалось 64 молекулы пировиноградной кислоты (ПВК). Какое количество молекул глюкозы подверглось расщеплению? В ответ запишите только число.

Приложения:

vladislglagolev: 32

Ответы

Автор ответа: borneo1

Гликолиз

С6Н12О6 + 2АДФ + 2Н3РО4 = 2С3Н4О3 + 2АТФ + 2Н2О

Пировиноградная кислота (ПВК)С3Н4О3

Глюкоза С6Н12О6

По уравнению реакции видно, что из 1 молекулы глюкозы образуется 2 молекулы ПВК.

Для образования 64 молекул ПВК нужно 64:2=32 молекулы глюкозы

Ответ: 32 молекулы глюкозы

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