Question

Решите уравнение а)(8-3х)-(4+2х)=9 б)х\3+х\6=1 ПОМОГИТЕ ПОЖАЛУЙСТА!!!!!!!!

Answer 1

$\displaystyle\bf\\1)\\\\(8-3x)-(4+2x)=9\\\\8-3x-4-2x=9\\\\-5x=9-4\\\\-5x=5\\\\x=-1\\\\\\2) \\\\\frac{x}{3} +\frac{x}{6} =1\\\\\\\frac{x}{3} \cdot 6+\frac{x}{6} \cdot 6=1\cdot 6\\\\2x+x=6\\\\3x=6\\\\x=2$

Answer 2

$\tt~1)~(8-3x)-(4+2x)=9;\\8-3x-4-2x=9;\\4-5x=9;\\-5x=9-4;\\-5x=5;\\x=5:(-5);\\\boxed{\tt~x=-1} . \\===============================\\\it\displaystyle2)~\dfrac{x}{3} +\frac{x}{6} =1;\\\frac{2x+x}{6} =1~~~|\cdot6;\\2x+x=6;\\3x=6;\\x=6:3;\\\boxed{\bf~x=2} .$