Question

решайте по братский??​

Answer 1

Объяснение:

$A=\left(\begin{array}{ccc}1&2\\3&4\\\end{array}\right)\ \ \ \ B=\left(\begin{array}{ccc}0&5\\6&8\\\end{array}\right) \ \ \ \ D=A*B-(A^2)=?\\A*B=\left(\begin{array}{ccc}1&2\\3&4\\\end{array}\right)*\left(\begin{array}{ccc}0&5\\6&8\\\end{array}\right)=\left(\begin{array}{ccc}a_1&a_2\\b_1&b_2\\\end{array}\right)*\left(\begin{array}{ccc}c_1&c_2\\d_1&d_2\\\end{array}\right)=$

$=\left(\begin{array}{ccc}a_1c_1+a_2d_1&a_1c_2+a_2d_2\\b_1c_1+b_2d_1&b_1c_2+b_2d_2\\\end{array}\right) =\left(\begin{array}{ccc}1*0+2*6&1*5+2*8\\3*0+4*6&3*5+4*8\\\end{array}\right) =\left(\begin{array}{ccc}12&21\\24&47\\\end{array}\right).$$(A^2)=A*A=\left(\begin{array}{ccc}1&2\\3&4\\\end{array}\right) *\left(\begin{array}{ccc}1&2\\3&4\\\end{array}\right)=\left(\begin{array}{ccc}1*1+2*3&1*2+2*4\\3*1+4*3&3*2+4*4\\\end{array}\right)=\\=\left(\begin{array}{ccc}7&10\\15&22\\\end{array}\right) .$

$D=A*B-(A^2)=\left(\begin{array}{ccc}12&21\\24&47\\\end{array}\right)-\left(\begin{array}{ccc}7&10\\15&22\\\end{array}\right)=\left(\begin{array}{ccc}5&11\\9&25\\\end{array}\right) .$