Question

РЕБЯТ, СРОЧНО НАДО, ПО БРАТСКИ!!! ​

Answer 1

Объяснение:

$\frac{4x^2}{2x-y}*\frac{2x^2}{6x^2+3xy}:\frac{12x^3}{4x^2-y^2}.\\1)\\\frac{4x^2}{2x-y}*\frac{2x^2}{6x^2+3xy} =\frac{4x^2*2x^2}{(2x-y)*3x*(2x+y)}=\frac{8x^4}{3x*(4x^2-y^2)}.\\2)\\\frac{8x^4}{3x*(4x^2-y^2)}:\frac{12x^3}{4x^2-y^2}= \frac{8x^4}{3x*(4x^2-y^2)}*\frac{4x^2-y^2}{12x^3} =\frac{8x^4*(4x^2-y^2)}{36x^4*(4x^2-y^2)}=\frac{2}{9} .$