Question

б) 4, (4) - 1,1(3)
помогите пожалуйста!​

Answer 1

$4,(4)-1,1(3)=4\frac{4}{9}-1\frac{13-1}{90}=4\frac{4}{9}-1\frac{12}{90}=(4-1)+(\frac{4}{9}-\frac{12}{90})=\\\\=3+\frac{40-12}{90}=3\frac{28}{90}=3\frac{14}{45}$