Question

Решите пожалуйста!! Подробно!

Answer 1

1) a) $3 y^2-3 y+1- left( 4 y-2 right) =3 y^2-3 y+1-4 y+2= 3 y^2-7 y+3$

б) $4 b^3 left( 3 b^2+b right) = 12 b^5+4 b^4$

2) $10x-5 = 2(8x+3)+5x$
$10x-5 = 16x+6+5x$
$-5-6 = 16x+5x-10x$
$-11 = 11x$
$x=-1$

3) $8ab-4a = 4a(2b-1)$
$18ab^3-9a^2b = 9ab(2b^2-a)$