Question

пожалуйста помогите ​

Answer 1

Ответ:

$20a^8*(9a)^2=20a^8*81a^2=1620a^{10}$

$(-b^5)^4*12b^6=(b^5)^4*12b^6=b^{20}*12b^6=12b^{26}$

$(3m^6n^3)^4*(-\frac{1}{81}m^9n)=-81m^{24}n^{12}*\frac{1}{81}m^9n=-m^{24}n^{12}m^9n=-m^{33}n^{13}$

$(0.2x^7y^8)^3*6x^2y^2=0.2^3*x^{21}y^{24}*6x^2y^2=(\frac{1}{5} )^3*x^{21}y^{24}*6x^2y^2=\frac{1}{125}x^{21}y^{24}*6x^2y^2=\frac{6}{125} x^{23}y^{26}$

$(-\frac{1}{2}ab^4)^3*(4a^6)^2=-(\frac{1}{2}ab^4)^3*16a^{12}=-\frac{1}{8}a^3b^{12}*16a^{12}=-a^3b^{12}*2a^{12}=-2a^{15}b^{12}$

$(-\frac{2}{3}x^2y)^5*(-\frac{3}{4}xy^2)^2=-(\frac{2}{3} x^2y)^5*(\frac{3}{4}xy^2)^2=-\frac{32}{243}x^{10}y^5*\frac{9}{16} x^2y^4=-\frac{2}{27} x^{10}y^5x^2y^4=-\frac{2}{27} x^{12}y^9$