Question

решить уравнение, даю 15 баллов!!​

Answer 1

Ответ:

x1 = 1; x2 = 3;

Answer 2

$\dfrac{3-2x}{x-2} =-x\\\\\\\dfrac{3-2x}{x-2} +x=0\\\\\\\dfrac{3-2x+x^{2} -2x}{x-2} =0\\\\\\\dfrac{x^{2} -4x+3}{x-2} =0\\\\\\\displaystyle\bf\\\left \{ {{x^{2} -4x+3=0} \atop {x-2\neq 0}} \right.\\\\\\\left \{ {{(x-1)(x-3)=0} \atop {x\neq 2}} \right. \\\\\\x-1=0 \ \ \Rightarrow \ \ x_{1} =1\\\\\\x-3=0 \ \ \Rightarrow \ \ x_{2} =3\\\\\\Otvet:1 \ ; \ 3$