Question

2x^2>5x^2(x+2)

неравенство решить

Answer 1

Ответ:

$2x^2>5x^2(x+2)\\\\5x^2(x+2)-2x^2<0\\\\x^2\, (5x+10-2)<0\\\\x^2\geq 0\ \ pri\ \ x\in R\ \ \ \Rightarrow \ \ \ 5x+10-2<0\ \ ,\ \ 5x<-8\ \ ,\ \ x<-1,6\\\\Otvet:\ \ x\in (-\infty \, ;-1,6\ )\ .$