Question

(18 целых 1/4 + 2 целые 1/6) : 1 целых 1/4

Answer 1

Ответ:

$(18\frac{1}{4}+2\frac{1}{6}):1\frac{1}{4} = ((18+2)+( \frac{1}{4}+ \frac{1}{6})):\frac{4*1+1}{4} =(20+( \frac{3+2}{12})):\frac{5}{4} = (20+\frac{5}{12})*\frac{4}{5} =\\\\= 20\frac{5}{12}*\frac{4}{5} =\frac{12*20+5}{12} *\frac{4}{5} =\frac{245}{12}*\frac{4}{5} = \frac{49}{12}*4=\frac{49}{3}=16\frac{1}{3}$