Question

(а^2+2с-в)-(3а^2-в) упростить​

Answer 1

Объяснение:

$(a {}^{2} + 2c - b) - (3a {}^{2} - b) = a {}^{2} + 2c - b - 3a {}^{2} + b = - 2a {}^{2} + 2c - b + b = - 2a {}^{2} + 2c$

Answer 2

(a^2+2c-b)-(3a^2-b)=a^2+2c-b-3a^2+b=-2a²+2c=2c-2a².