Question

С ПОДРОБНЫМ РЕШЕНИЕМ ПЛЗ​

Answer 1

Ответ:

$x=2,5\ \ ,\ \ y=-1,5\\\\\\\displaystyle \Big(\frac{x}{y}-\frac{y}{x}\Big):\frac{x+y}{5xy}=\frac{x^2-y^2}{xy}:\frac{x+y}{5xy}=\frac{(x-y)(x+y)}{xy}\cdot \frac{5xy}{x+y}=5(x-y)=\\\\\\=5\cdot (2,5+1,5)=5\cdot 4=20$

Использована формула разности квадратов:  $x^2-y^2=(x-y)(x+y)$

Answer 2

$\displaystyle\bf\\\Big(\frac{x}{y}-\frac{y}{x} \Big):\frac{x+y}{5xy}=\frac{x^{2} -y^{2} }{xy} :\frac{x+y}{5xy} =\frac{(x+y)(x-y)}{xy} \cdot\frac{5xy}{x+y} =5(x-y)\\\\\\x=2,5 \ \ ; \ \ y=-1,5\\\\\\5(x-y)=5\cdot\Big(2,5-(-1,5)\Big)=5\cdot(2,5+1,5)=5\cdot4=20$