Question

(x²-2x-5)²-2(x²-2x-5)=3​

Answer 1

Объяснение:

$(x {}^{2} - 2x - 5) {}^{2} - 2(x {}^{2} - 2x - 5) = 3$

$(x {}^{2} - 2x - 5) {}^{2} - 2(x {}^{2} - 2x - 5) - 3 = 0$

$t {}^{2} - 2t - 3 = 0$

$t = - 1$

$t = 3$

$x {}^{2} - 2x - 5 = - 1$

$x {}^{2} - 2x - 5 = 3$

$x = 1 + \sqrt{5}$

$x = 1 - \sqrt{5}$

$x = - 2$

$x = 4$

Ответ:

$x _{1} = - 2,x _{2} = 1 - \sqrt{5} ,x _{3} = 1 + \sqrt{5} ,x _{4} = 4$

Альтернативная форма:

$x _{1} = - 2,x _{2} ≈ - 1.23607,x _{3} ≈3.23607,x _{4} = 4$