Question

а-8/а в квадрате-4 + 4/а-2​

Answer 1

Ответ:

$\frac{a - 8}{ {a}^{2} - 4} + \frac{4}{a - 2} = \frac{a - 8}{(a - 2)(a + 2)} + \frac{4}{a - 2} = \frac{a - 8 + 4(a + 2)}{(a - 2)(a + 2)} = \frac{a - 8 + 4a + 8}{(a - 2)(a + 2)} = \frac{5a}{(a - 2)(a + 2)}$