Предмет: Физика, автор: sergeybaluev

Во время удара по хоккейной шайбе массой 250 г, она движется с ускорением 1500 м/с^2. Определите силу удара.

Ответы

Автор ответа: IIIceMage
0
F=ma; m=0.25 кг; a=1500 м/с^2 Сдедовательно F=0.25*1500=25*15=375(H)
Автор ответа: sergeybaluev
0
Благодарю.
Автор ответа: IIIceMage
0
Незачто
Автор ответа: Аноним
0
Дано  m=0,25 кг  a=1500 м/с2    F- ?
по второму закону Ньютона
F = m*a=0,25*1500=375 Н
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