Question

Sos даю 100б
7.8^0 х^-10 у^-13 z^0/7^-2 a^6 в^-15 с^-7=
Вопрос на фотке

Answer 1

Объяснение:

$\frac{ {7.8}^{0} {x}^{ - 10} {y}^{ - 13} {z}^{0} }{ {7}^{ - 2} {a}^{6} {b}^{ - 15} {c}^{ - 7} } = \frac{1 \times {7}^{2} \times {b}^{15} \times {c}^{7} \times 1}{ {a}^{6} \times {x}^{10} \times {y}^{13} } = \frac{49 {b}^{15} {c}^{7} }{ {a}^{6} {x}^{10} {y}^{13} }$