Question

Преобразуйте рациональные выражение к несократимой дроби:​

Answer 1

$\frac{3x}{x-3}+\frac{x+5}{6-2x}*\frac{54}{x^2+5x}=\frac{3x}{x-3}+\frac{54(x+5)}{2(3-x)x(x+5)}=\frac{3x}{x-3}-\frac{27}{x(x-3)}=\\\\=\frac{3x^2-27}{x(x-3)}=\frac{3(x^2-9)}{x(x-3)}=\frac{3(x-3)(x+3)}{x(x-3)}=\frac{3(x+3)}{x}$

Answer 2

Ответ:

$\frac{3x}{x - 3} + \frac{x + 5}{6 - 2x} \times \frac{54}{ {x}^{2} + 5x} = \frac{3x}{x - 3} + \frac{x + 5}{2(3 - x)} \times \frac{54}{x(x + 5)} = \frac{3x}{x - 3} - \frac{ 54}{2x(x - 3)} = \frac{6 {x}^{2} - 54}{2x(x - 3)} = \frac{6( {x }^{2} - 9 )}{2x(x - 3)} = \frac{3(x - 3)(x + 3)}{x(x - 3)} = \frac{3(x + 3)}{x} = \frac{3x + 9}{x}$