Question

Помогите решить пример

Answer 1

Ответ:

x=4

Объяснение:

$\frac{3}{x^{2} -9}+\frac{x(x-3)}{x^{2} -9}=\frac{x^{2} -9}{x^{2} -9}\\3+x^{2} -3x=x^{2} -9\\-3x=-12\\3x=12\\x=4$

Answer 2

$\displaystyle \frac{3}{x^2-9} +\frac{x}{x+3} =1;~ ODZ:~x\neq-3~;~x\neq3;\\\frac{3}{(x-3)(x+3)} +\frac{x^{(x-3)} }{x+3} =1;\\\frac{3+x*(x-3)}{(x-3)(x+3)} =1;\\\frac{3+x^2-3x}{(x-3)(x+3)} =1~~|*\bigg((x-3)(x+3)\bigg);\\3+x^2-3x=(x-3)(x+3);\\3+x^2-3x=x^2-9;\\3-3x=-9;\\-3x=-9-3;\\-3x=-12;\\x=12:3;\\x=4.$