Question

Возвести в степень
${(0.2 \sqrt[3]{15}) }^{6}$
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Answer 1

$(0,2\sqrt[3]{15})^6=(\frac{1}{5}\sqrt[3]{5*3})^6=(5^{-1}*5^{\frac{1}{3}}*3^{\frac{1}{3}})^6=5^{-1*6}*5^{\frac{6}{3}}*3^{\frac{6}{3}}=\\\\=5^{-6}*5^2*3^2=5^{-6+2}*9=5^{-4}*9=\frac{9}{5^4}=\frac{9}{625}$