Question

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Answer 1

Объяснение:

1)

$\frac{3a - b}{ab} - \frac{5b + 3a}{ab} = \frac{3a - b - 5b - 3a}{ab} = \frac{ - 6b}{ab} = - \frac{6}{a}$

2)

$\frac{9m + 2 {k}^{2} }{5k} - \frac{9m - 3 {k}^{2} }{5k} = \frac{9m + 2 {k}^{2} - 9m + 3 {k}^{2} }{5k} = \frac{5 {k}^{2} }{5k} = k$

3)

$\frac{5b - {m}^{2} }{4 {m}^{3} } - \frac{ {m}^{2} + 5b }{4 {m}^{3} } = \frac{5b - {m}^{2} - {m}^{2} - 5b}{4 {m}^{3} } = - \frac{2 {m}^{2} }{4 {m}^{3} } = - \frac{1}{2m}$

4)

$\frac{4a - 3}{6a} - \frac{a + 8}{6a} - \frac{5 - a}{6a} = \frac{4a - 3 - a - 8 - 5 + a}{6a} = \frac{4a - 16}{6a} = \frac{2(2a - 8)}{6a} = \frac{2a - 8}{3a}$

$\frac{3a - 5}{4 {a}^{2} } + \frac{5 + a}{4 {a}^{2} } = \frac{3a - 5 + 5 + a}{4 {a}^{2} } = \frac{4a}{4 {a}^{2} } = \frac{1}{a}$

$a = \frac{1}{2}$

$a \frac{1}{ \frac{1}{2} } = 2$