Question

9x3-7x2-2x=0 решите уравнение

Answer 1

$9x^3-7x^2-x=0\\x(9x^2-7x-2) = 0\\x(9x^2+2x-9x-2) = 0\\x(x(9x+2)-(9x-2)) = 0\\x(9x+2)(x-1) = 0\\\\x_1 = 0\\\\9x+2=0\\x_2 = - \dfrac{2}{9}\\\\\\x - 1 = 0\\x_3 = 1$