Question

Знайти модуль вектора a(6;-8)
срочно!!!!!!​

Answer 1

$| \overrightarrow{a}| = \sqrt{a_ x {}^{2} + a_y {}^{2} } = \sqrt{6 {}^{2} + ( - 8) {}^{2} } = \sqrt{36 + 64} = \sqrt{100} = 10.$